Why do digital cameras need exposure time instead of reading the sensor instantly?
Asked 1/9/2013
3 views
2 answers
0
I’m trying to understand why digital cameras need a nonzero exposure time. My simplified mental model is that a camera sensor is a 2D array of photodiodes, and brighter light should immediately produce a stronger electrical signal at each pixel. If that’s true, why can’t the camera just read those values almost instantly and form an image right away? Where is that model incomplete? Do digital sensors actually need time to accumulate light, and are there any designs that work more like an instantaneous readout?
Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0
Photography Stack Exchange contributor
13y ago
2 Answers
18
I'm visiting from Electronics, so I'll add a little bit of electronics/semiconductor physics background to a couple of the answers you've already gotten.
The key misunderstanding I think you have is that a photodiode doesn't create a voltage in response to light, it creates a current. Each photon that hits the photodiode generates a mobile electron inside the device (really an "electron-hole pair", but if you want that level of detail you'd better take the question over to EE.SE). Millions of electrons together constitute a measurable electrical current. Finally when this current is used to charge a capacitor, then you have a measurable voltage which can be sensed or recorded to form a pixel in your image.
This is why, as cmason says, the sensor needs some time to fill each "bucket", and as mattdm says, it takes time for an accumulator to fill to the point it can be measured to form an image.
Originally by user14526. Source · Licensed CC BY-SA 4.0
user14526
13y ago
0
Generated from our catalog & community — verify before relying on it.
The missing piece is that a sensor pixel doesn’t really give you a strong, instantly useful voltage. A photodiode primarily generates charge/current when photons hit it. That charge is collected in a tiny capacitor or “well,” and the camera measures the accumulated charge after some time.
Exposure time is needed because the signal from light is very small, especially in dim scenes. If you read the pixel too quickly, the useful signal may be similar in size to read noise and other electronic noise. Letting the pixel collect photons for longer improves the signal relative to noise.
So a digital exposure is essentially a counting process: brighter areas fill the well faster, darker areas more slowly. At the end of the exposure, the stored charge is read out and converted into a pixel value.
In principle, you could try to read almost instantly, but that would be like using an extremely high ISO: very noisy unless the light is very bright or the pixels are very large. Some sensor ideas involve multiple readouts during one exposure, but standard cameras still rely on accumulation because it gives a cleaner, more useful image.
Recommended products
UniqueBot
AI13y ago
Your Answer
Related Questions
What’s the difference between a photodiode, a photosite, and a pixel?
Why doesn’t a leaf shutter overexpose the center of the image?
What limits the frame rate and readout patterns of a CMOS image sensor?
How does a Lytro light-field camera work compared with a traditional camera?
Why do DSLR sensors on the ISS develop hot/dead pixels faster than cameras on satellites or rovers?