Is a 300mm lens suitable for photographing horse jumping on a Nikon D3400?

Asked 6/17/2025

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I’m photographing a horse-jumping event and want to focus on one rider. I use a Nikon D3400 and am comfortable with aperture priority, but with this older manual-focus lens I’ll need to work differently because the camera doesn’t fully recognize it. I have a Nikon AF Nikkor 300mm f/4 ED and I’m unsure whether 300mm is a good focal length for this type of event, especially since I don’t yet know how far I’ll be from the jumps. Is there a recommended shooting distance, or is lens choice mainly determined by how much of the scene I want to include?

Originally by jlw9406. Source · Licensed CC BY-SA 4.0

jlw9406

11mo ago

2 Answers

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Working out the focal length from the distance and field of view

There is no "recommended" distance for any lens. The focal length you choose depends on the field of view that you require and your distance away.

It is easiest to visualise what is going on by thinking about a pinhole camera: diagram of pinhole camera The basic rule of perspective can be deduced from the geometry of this diagram:

$$\frac{\textit{Object size}}{\textit{Image size}}=\frac{\textit{Object distance}}{\textit{Image distance}}$$

For a camera with a lens, the image distance is approximately equal to \$f\$, the focal length of the lens, so: $$\frac{\textit{Object size}}{\textit{Image size}} = \frac{\textit{Object distance}}{f}$$ The horizontal field of view is the width of an object whose image exactly fills the sensor from one side to the other.

The sensor for a full-frame camera is 36mm wide. For a camera with a crop factor of 1.5, the sensor is \$\frac{36}{1.5}=24\$ mm wide.

So, for a field of view that is \$x\$ metres wide horizontally, at a distance of \$y\$ metres, you need to use a focal length of \$f\$ mm, given by this formula for a FF camera: $$f=\frac{36y}{x}$$ or by this formula for a 1.5 crop camera: $$f=\frac{24y}{x}$$ This assumes that the camera is used in landscape format (the horizontal dimension is greater than the vertical dimension).

For example, if you are using a 1.5x crop camera and want a field of view that is 3 metres wide at a distance of 20 metres, then you need to use a focal length of \$\frac{24\,\times\,20}{3}=160\$ mm.

Of course, if the focal length is decided already (because it is the only lens available), then you can work out the distance away you need to stand to obtain a certain field of view for your 1.5x crop camera: $$y=\frac{fx}{24}$$ For example, if you want a horizontal field of view 3 metres wide and the focal length is 300 mm, then you need to be at a distance of \$\frac{300\,\times\,3}{24}=37.5\$ metres. Again, this is for a 1.5x crop camera.

Originally by Tom Axford. Source · Licensed CC BY-SA 4.0

Tom Axford

11mo ago

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AI Answer

Generated from our catalog & community — verify before relying on it.

A 300mm can work well, but there isn’t a single “recommended distance” for it. The right focal length depends on your distance from the jump and how tightly you want to frame the rider and horse.

In general, focal length controls field of view: the farther away you are, the longer the lens you need to fill the frame. A 300mm on a Nikon D3400 (DX/crop sensor) gives a fairly narrow angle of view, so it’s better if you’re shooting from farther back or want tight shots of the rider clearing a jump. If you’re close to the action, 300mm may be too tight.

So the key question is not the lens’s “best distance,” but whether its field of view matches where you’ll be allowed to stand. If possible, scout the venue or be prepared that you may need to move position to make 300mm practical.

UniqueBot

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11mo ago

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