How is focal length defined for a 180° fisheye lens?

Asked 10/26/2017

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I understand the usual definitions of focal length in terms of collimated rays and image formation, but fisheye lenses can cover up to 180° and use non-rectilinear projections. How is focal length defined for a fisheye lens, and how does that relate to its field of view and image mapping?

Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0

Photography Stack Exchange contributor

8y ago

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Unlike "normal" (rectilinear) lens, there are many types of fisheye lenses, using different projections. The same focal length (f) can give different image size and/or different distortions, depending on the type.

Example:

Assuming your 8mm lens uses the most basic equidistant fisheye (180° degrees field of view = -90°..+90°)

R = f · θ

8mm · π/2 ≈ 12.56mm

So, rays from -90°..+90° map to -12.56...+12.56mm on the image sensor or film, creating a 25mm circle. From calculation we can learn that such lens would not cover the 36x24mm full frame image area.

Fisheye projections from https://wiki.panotools.org/Fisheye_Projection

Originally by user32811. Source · Licensed CC BY-SA 4.0

user32811

8y ago

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AI Answer

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Focal length for a fisheye is defined the same basic way as for other lenses: it is the distance from the lens’s rear nodal/principal point to the image plane when focused at infinity. In other words, rays from a single point at infinity are brought to focus at the focal plane a focal-length distance behind the lens.

What changes with a fisheye is not the definition of focal length, but the projection used to map scene angle onto the sensor. Unlike a rectilinear lens, fisheyes may be equidistant or use other mappings, so two fisheyes with the same focal length can render angle and distortion differently.

For example, an equidistant fisheye uses:

R = f × θ

where θ is the angle from the optical axis (in radians) and R is the image height. For a 180° field of view, θ runs to ±90° = ±π/2, so an 8mm equidistant fisheye gives:

R = 8 × π/2 ≈ 12.6mm

That produces about a 25mm image circle. So focal length still has its normal optical meaning; field of view and image coverage then depend on the fisheye’s projection design and sensor size.

UniqueBot

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8y ago

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