How is focal length defined for a 180° fisheye lens?
Asked 10/26/2017
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I understand the usual definitions of focal length in terms of collimated rays and image formation, but fisheye lenses can cover up to 180° and use non-rectilinear projections. How is focal length defined for a fisheye lens, and how does that relate to its field of view and image mapping?
Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0
Photography Stack Exchange contributor
8y ago
2 Answers
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Unlike "normal" (rectilinear) lens, there are many types of fisheye lenses, using different projections. The same focal length (f) can give different image size and/or different distortions, depending on the type.
Example:
Assuming your 8mm lens uses the most basic equidistant fisheye (180° degrees field of view = -90°..+90°)
R = f · θ
8mm · π/2 ≈ 12.56mm
So, rays from -90°..+90° map to -12.56...+12.56mm on the image sensor or film, creating a 25mm circle. From calculation we can learn that such lens would not cover the 36x24mm full frame image area.
Originally by user32811. Source · Licensed CC BY-SA 4.0
user32811
8y ago
0
Generated from our catalog & community — verify before relying on it.
Focal length for a fisheye is defined the same basic way as for other lenses: it is the distance from the lens’s rear nodal/principal point to the image plane when focused at infinity. In other words, rays from a single point at infinity are brought to focus at the focal plane a focal-length distance behind the lens.
What changes with a fisheye is not the definition of focal length, but the projection used to map scene angle onto the sensor. Unlike a rectilinear lens, fisheyes may be equidistant or use other mappings, so two fisheyes with the same focal length can render angle and distortion differently.
For example, an equidistant fisheye uses:
R = f × θ
where θ is the angle from the optical axis (in radians) and R is the image height. For a 180° field of view, θ runs to ±90° = ±π/2, so an 8mm equidistant fisheye gives:
R = 8 × π/2 ≈ 12.6mm
That produces about a 25mm image circle. So focal length still has its normal optical meaning; field of view and image coverage then depend on the fisheye’s projection design and sensor size.
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