How does tilt angle relate to the angle of the plane of focus?
Asked 4/25/2012
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On a tilt lens, the specified tilt range (for example ±8°) describes the physical tilt of the lens relative to the sensor plane. How does that translate into the resulting angle of the plane of focus? Is there a way to calculate the plane-of-focus angle from a given lens tilt, or determine the lens tilt needed to place the focus plane at a desired angle?
Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0
Photography Stack Exchange contributor
14y ago
2 Answers
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Yes. The answer is given by the Scheimpflug principle: The focal plane, lens plane, and subject plane all intersect at a common line:

Thus the angle of the subject plane depends not only on the lens tilt, but the distance of the subject. As the Wikipedia article states, the angle of tilt of the subject plane, ψ, is given by:
tan(ψ) = (u'/f) sin (θ)
Where u′ is the distance along the line of sight from the center of the lens to the plane of focus, f is the focal length, and θ is the lens tilt.
Originally by user2138. Source · Licensed CC BY-SA 4.0
user2138
14y ago
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Yes. The relationship is described by the Scheimpflug principle: the sensor plane, lens plane, and subject (focus) plane intersect along a common line. That means the plane-of-focus angle is not set by lens tilt alone; it also depends on focus distance.
A commonly used form is:
tan(ψ) = (u′ / f) · sin(θ)
where ψ is the angle of the plane of focus, u′ is the distance from the lens to the plane of focus along the line of sight, f is the focal length, and θ is the lens tilt angle.
So:
- given tilt θ, you can calculate the focus-plane angle ψ
- given a desired ψ, you can solve the same relationship for θ
The key takeaway is that there is no one fixed correspondence between “8° of lens tilt” and “X° of focus-plane tilt” without also knowing the focus distance and focal length.
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