How do ND filter stops relate to full-, half-, and third-stop camera increments?

Asked 11/25/2019

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If I use a 10-stop ND filter such as an ND1000/ND1024, do I always add 10 stops of exposure no matter whether my camera is set to full-stop, 1/2-stop, or 1/3-stop adjustments? In other words, is the filter rating measured in full stops, and how many camera adjustment clicks would that be for each increment setting?

Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0

Photography Stack Exchange contributor

6y ago

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It sounds like you are confusing "stops" with "steps". A photographic stop is a doubling of light exposure.

If you can adjust your exposure by 1/2- or 1/3- stop increments, then you would need 2 or 3 increments adjustment (respectively) to achieve a 1 stop change in exposure. So when using a 10-stop ND filter, you would need 20 steps if you were adjusting in 1/2-stop increments, or 30 steps if using 1/3-stop increments.

If you were shooting a scene, without ND filter, and your exposure settings dictated a 2-second shutter speed, then a 10-stop ND filter would necessitate increasing the exposure by a factor of 210 (i.e., 1024). Thus, you'd set the shutter speed to 2 * 1024 = 2048 = 34.133... min = 34:08.

Note: a ND1024 filter is precisely a 10-stop (i.e., 210 = 1024 multiplier) ND filter. A ND1000 is actually a multiple of 1000, not 1024. Thus the change from 2-second non-ND exposure would be 2 * 1000 = 33.33... min = 33:20. However, the ratio difference of 1024/1000 is only 2.4%. In terms of stops, the difference is log2(1.024) = 0.034 stops, a trivially small exposure difference that you won't be able to discern between two images, and way below the smallest precision of any commercially-available DSLR or MILC camera.


Regarding fractional-stop ND filters, they aren't common, but they do exist. I use mostly Lee filters. While I don't own fractional-stop filters, Lee makes ND 0.45 (1.5 stop) and ND 0.75 (2.5 stop) filters. If one were to use either of those filters, the exposure settings would need to be adjusted by 21.5 ≈ 2.83, or 22.5 ≈ 5.66, respectively.


Now, regarding fractional-stop exposure settings in camera: it doesn't matter if your camera is able to set exposure settings in fractional-stop increments. Whatever the "correct"/desired exposure settings a particular scene calls for without a ND filter in front of the lens, you need to increase the total exposure by the number of stops as called for when using your filter.

For instance, let's say a particular ISO 100, ƒ/8 shot is metered for 1/50" . A 10-stop ND filter would still require increasing the shutter duration from 1/50" to 1/50 * 1024 = 20.48 seconds. I'm not aware of any cameras or shutter remotes that allow fractional seconds beyond 2.5", so you can just pick 20 or 21 seconds. The difference is only 0.07 stops (i.e., less than 1/10 stop, still less than any camera can control for).

Related questions and links:

Originally by user11924. Source · Licensed CC BY-SA 4.0

user11924

6y ago

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Yes. A filter rated at 10 stops always means 10 stops of light reduction, regardless of whether your camera is set to full-, half-, or third-stop increments.

The key distinction is between a stop and a camera adjustment step:

  • 1 stop = doubling or halving the exposure
  • with 1/2-stop settings, 2 clicks = 1 stop
  • with 1/3-stop settings, 3 clicks = 1 stop

So for a 10-stop ND filter, you would adjust exposure by:

  • 10 clicks at full-stop increments
  • 20 clicks at 1/2-stop increments
  • 30 clicks at 1/3-stop increments

If you’re changing shutter speed only, multiply the original shutter time by 2^10 = 1024. For example, if the metered shutter speed without the filter is 2 seconds, with a 10-stop ND filter it becomes about 2048 seconds, or roughly 34 minutes.

ND1000 is a rounded label; ND1024 corresponds exactly to 10 stops.

UniqueBot

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6y ago

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