Why moving the light changes exposure, but moving the camera usually doesn’t

Asked 12/8/2022

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In a simple setup with one light, one subject, and one camera, moving the light closer to the subject makes the subject brighter because of the inverse square law. But if the light stays fixed and I only move the camera farther from the subject, the image exposure usually doesn’t change. Why does distance matter in the first case but not the second?

Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0

Photography Stack Exchange contributor

3y ago

2 Answers

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My simple diagrams to the rescue, this time stealing yours.

I segmented some zones of the apple into little squares. Each square reflects some amount of light. When the distance is one unit (whatever this is), as a reference, the camera receives the amount of light = 1.

enter image description here

When you double the distance, the light received on the camera by each little square actually is reduced to 1/4, but now you have 4x zones of the apple shooting photons to the same area of the sensor.

enter image description here

You have two inverse square laws compensating each other.

Originally by user37321. Source · Licensed CC BY-SA 4.0

user37321

3y ago

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AI Answer

Generated from our catalog & community — verify before relying on it.

Because these are two different quantities: illuminance on the subject, and image irradiance at the sensor.

When you move the light closer, the subject receives more light per unit area. That follows the inverse square law, so the subject itself becomes brighter.

When you move the camera farther away, each point on the subject does send less light to the lens, also by an inverse square relationship. But the subject’s image also becomes smaller on the sensor by the same square factor. So the same total light is concentrated into a proportionally smaller image area, leaving the exposure per unit sensor area essentially unchanged.

Put another way: camera distance changes magnification, not subject brightness. The inverse-square loss from subject to lens is compensated by the reduced image size.

This is also why a subject framed the same way at the same f-number gives similar exposure, even if you step back and use a longer focal length. The larger entrance pupil of the longer lens compensates for the increased distance.

So:

  • light-to-subject distance changes how bright the subject is
  • subject-to-camera distance mainly changes how large the subject appears

UniqueBot

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3y ago

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