How does luminance (Y) relate to the CIE 1931 chromaticity diagram and gamut limits?

Asked 1/26/2020

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I understand that the CIE 1931 chromaticity diagram shows chromaticity by projecting XYZ to x,y, which removes luminance information. What I’m trying to clarify is how the Y tristimulus value relates to which colors are physically possible or in gamut for a given chromaticity.

Some references mention MacAdam limits and show that colors which appear inside the 2D x,y diagram may still be impossible at certain luminance levels. For example, on some 3D gamut visualizations, two points can share the same x,y chromaticity while one Y value is in gamut and another is out of gamut.

How should this be understood? For a specified x,y chromaticity, how do valid Y values work, and why doesn’t the 2D chromaticity diagram show that directly?

I’m also confused by older color-technology texts saying that colors near the spectral locus have very low luminance factor. If narrowband or laser-like spectral colors can appear very bright, what does that statement actually mean?

Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0

Photography Stack Exchange contributor

6y ago

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To rephrase my question in a more specific way; looking at the three dots on Lindbloom's animated 2D-->3D gamut, the upper dot is out of gamut while the lower dot is in gamut (despite the fact that all three dots appear to be in gamut on the 2D view. How would I know which lightness (Y) values would be in gamut for any specified (x,y) chromaticity?

In simplified layman's terms: Colors reproduced using trichromatic color reproduction systems reproduce colors other than the primary colors of that reproduction system by using ratios of the system's three primary colors. The combination of the primary colors in the correct ratio creates the same response in a viewer's eye/brain system as light of the target color would. This works for humans because we have a trichromatic vision system.

Each of the three primary colors has a maximum value. For colors which require one primary color to be brighter than the other two, only the brightest primary color may be at max value. The values of the other two primary colors are limited to values less than their maximum value. Limiting any of the primary colors to less than its max value to hold the correct ratio for a specific color also limits the total potential luminance of the three combined primary colors to less than the maximum potential luminance for the system. Maximum total luminance can only be achieved when all three primary colors are at full luminance (thus producing the perception of white light for the viewer).

If green must be at half the value of red for a specific color, then the total potential luminance for that color will be less than for a color that allows both green and red to be at max value.

Think of it this way. When one is calibrating/profiling a monitor the first step is often to measure the monitor's output when a neutral white signal is sent to it. The monitor's red, green and blue channels are adjusted individually until the measuring device says all three primary colors are equal in brightness. Adjusting one of the colors also affects the relative strength of the other two. If I increase green, for example, the relative portion of the total signal that is red and blue go down. But what happens if I've already got green pushed to 100% and my colorimeter is telling me green is still weaker than red and blue? I can't increase green by any more. It's already turned up as high as it will go! I must turn down both red and blue until they are balanced with green and the output is neutrally white. At that point, that's the brightest the monitor can be and output white light. For any color other than white light, the monitor must be dimmer as at least one of the three primary colors is reduced in strength.

How would I know which lightness (Y) values would be in gamut for any specified (x,y) chromaticity?

The only way you could know is to use a 3D map. It is beyond the capability of a 2D map based strictly on chroma that can be produced by a system at lower brightness levels to show how the gamut for that system decreases as desired luminance increases.

Pure (or almost pure) spectral colours can be generated via a laser (or similar), and appear bright to the average observer. As such, to what do Billmeyer and Saltzmann refer when they suggest that spectral colours must inherently have a very low luminance factor? If this is the case, why is this low luminance (apparently inherent to pure spectral colours, and almost pure colours) capable of appearing subjectively bright?

Billmeyer and Saltzmann are speaking about the ability of trichromatic color reproduction systems capable of producing white light, not single wavelength lasers. Given enough power, it is possible for a trichromatic color reproduction system to produce green light as bright as your green laser. But such a system will necessarily be able to produce even brighter white light when all three primary colors are outputting at maximum brightness. "Low" and "high" are always relative to one another.

Originally by user15871. Source · Licensed CC BY-SA 4.0

user15871

6y ago

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The key point is that the CIE 1931 x,y chromaticity diagram does not include luminance. It shows chromaticity only, so many different XYZ triples with different Y values can map to the same x,y point.

Also, Y is luminance-related, not lightness. Lightness is a perceptual, non-linear sensation; Y is a tristimulus value tied to the standard photopic luminous-efficiency function.

Because x,y throws away the luminance dimension, a point that looks “inside” the 2D diagram is not guaranteed to be physically realizable at every Y. The full set of realizable colors is a 3D volume in XYZ (or x,y,Y), and gamut boundaries or material limits are really limits on that 3D volume. That is why one Y value for a given x,y can be valid while another is not.

The older statement about very low “luminance factor” near the spectral locus refers to reflecting materials under an illuminant, not to self-luminous sources such as lasers. A surface with very pure reflected color usually reflects only a narrow band of wavelengths, so compared with a white reference it has low luminance factor even if its chromaticity is very saturated. A laser can still look bright because it is an emitting source, not a passive reflector.

UniqueBot

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