How do you read a film characteristic curve, and how does log exposure relate to f-stops?
Asked 7/1/2015
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I’m trying to understand a film characteristic (H&D) curve for slide film like Velvia 50.
Specifically:
- What does a density value of 0.0 mean on the vertical axis?
- How do you relate log H (log exposure) to exposure values or f-stops?
- If the roughly linear section runs from about -0.3 to -1.65 on the log H axis, how many stops of exposure range is that?
- Is it correct to place an 18% gray subject in the middle of the straight-line section of the curve for the “best” exposure?
Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0
Photography Stack Exchange contributor
11y ago
2 Answers
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Pretty much all your questions are answered in this guide:
- Film Shooters Collective: A Practical Guide to Using Film Characteristic Curves
What does 0.0 value represents (how to interpret it)?
This is represented as a log scale, so 0.0 passes a certain value of light, 1.0 passes 1/10 that amount of light, 2.0 passes 1/100 that amount of light, and so on. So the density gives somewhat of a dynamic range / contrast ratio. 0.0 would presumably represent 100% light transmitted, ie perfectly transparent area of film.
Obviously with slide film like the Velvia, the density is at its greatest in the blacks (left hand side of exposure) because that's where it blocks the most light, so the density relates to the blackest parts of the image. On negative film the density increases to the right instead for the film.
How do I convert log H to EV?
Convert log lux seconds to EV (absolute - for a given ISO):
ΔEV = log2 [10 x Log Lux Seconds – log10(10/ISO)]
Or just convert a change (delta) in lux seconds (ΔLog Lux Seconds)
ΔEV = log2 (10 x ΔLog Lux Seconds)
Source: the guide I linked above.
Am I correct that "the best" exposure would be to map average gray point (18% reflected) to (3.0D - 05D) / 2 = 1.25D density? I.e. to the very middle of the linear part on Y axis?
Obviously how to expose is a choice to make, but it makes sense to try and fit as many of the lightest and darkest parts of the scene into the linear part of the curve to represent them accurately.
In the general sense average grey (18% card) mapped to, say, the density of the mid part of the most linear part of the curve, like you suggest, seems to make sense.
Originally by user3422. Source · Licensed CC BY-SA 4.0
user3422
11y ago
0
Generated from our catalog & community — verify before relying on it.
On a characteristic curve, the vertical axis is film density, which is logarithmic. A density of 0.0 means no added density: essentially fully transparent film. Density 1.0 transmits 1/10 as much light, 2.0 transmits 1/100, etc.
The horizontal axis, log H, is the logarithm of exposure. One stop is a 2× change in exposure, so in base-10 log units:
1 stop = log10(2) ≈ 0.301
So to convert a log-H difference to stops, divide by 0.301. For your example:
1.35 / 0.301 ≈ 4.5 stops
So that straight-line region spans about 4.5 stops of exposure.
As for placing 18% gray in the middle of the straight-line portion: that’s a reasonable way to think about maximizing tonal headroom on both sides, but it isn’t automatically “the best” exposure in every practical situation. Characteristic curves describe how the film responds, but actual exposure choices also depend on the scene and what tones you most want to preserve. With slide film especially, exposure latitude is limited, so protecting important highlights is often critical.
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