How do I adjust shutter speed when changing aperture in manual mode?

Asked 9/18/2016

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I’m learning manual exposure on a Canon Rebel T5. If my meter is centered at ISO 200 with an exposure of f/11 at 1/60 sec, how do I calculate the matching shutter speed if I change the aperture to f/22? My camera uses 1/3-stop increments, so I’d also like to understand the general rule for trading aperture and shutter speed.

Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0

Photography Stack Exchange contributor

9y ago

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The best way to work with f/numbers is to memorize the f-number set. The number set for the f/stops: 1 – 1.4 – 2 – 2.8 – 4 – 5.6 – 8 – 11 – 16 – 22 – 32 Each number going right is its neighbor on the left multiplied by 1.4. Each number going left is its neighbor on right divided by 1.4 (or multiplied by 0.7).

Your exposure for this given situation is f/11 @ 1/60 of a second. Your desire is to move the aperture to f/22. Inspect the f/number set above. Note f/22 is two (2) f/stops away from f/11. Going right is smaller aperture diameters (more closed down – less light will be allowed to enter the camera). Now each f/stop represents a doubling or halving of light energy that is allowed to transverse the lens. Your desire is to reduce the aperture two (2) f/stops. To compensate, you must slow the shutter the equivalent of two f/stops. This action will allow more time for the light to play on the image sensor during the exposure. In other words, slowing the shutter allows more time for the exposing light to accumulate; thus you are compensating for the aperture size reduction by allowing more time for the exposing light to collect on the image sensor.

To accomplish this -- if you slow the shutter from 1/60 of a second to 1/30 of a second, this action doubles the time the light can play on the sensor. However, you desire a two f/stop change, so you must do this again. The final and correct shutter speed will be 1/15 of a second. This is a 4X or two stop change.

Mathematically, to make a two stop change to the shutter, remember each change of the shutter is the equivalent of a 2X change. You need to do this twice for a 2 f/stop change; thus the change in shutter speed is 4X. To accomplish, you multiply the original shutter speed by 4. Thus 1/60 X 4/1 = 4/60. This fraction can be reduced 4/60 = 2/30 = 1/15. Nobody said this stuff is easy!.

Originally by user44949. Source · Licensed CC BY-SA 4.0

user44949

9y ago

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AI Answer

Generated from our catalog & community — verify before relying on it.

Use equivalent exposure: if you close the aperture, you must slow the shutter by the same number of stops to keep the exposure the same.

Full-stop aperture sequence: f/1, 1.4, 2, 2.8, 4, 5.6, 8, 11, 16, 22, 32.

From f/11 to f/22 is 2 full stops smaller:

  • f/11 → f/16 = 1 stop less light
  • f/16 → f/22 = 1 more stop less light

So you must add 2 stops of shutter time:

  • 1/60 → 1/30 = +1 stop
  • 1/30 → 1/15 = +1 stop

So the equivalent exposure is f/22 at 1/15 sec.

General rule: every 1 stop change in aperture requires a 1 stop opposite change in shutter speed. If aperture lets in half as much light, shutter must stay open twice as long. If aperture lets in twice as much light, shutter can be twice as fast.

With 1/3-stop settings, the same idea applies in smaller steps, but memorizing the full-stop aperture series makes the math much easier.

UniqueBot

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9y ago

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