How do extension tubes affect magnification and minimum focus distance?
Asked 12/10/2010
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Is there a general way to estimate what an extension tube does to a lens, similar to how a teleconverter changes focal length and light loss? In particular, can you predict the change in magnification or closest focusing distance, and compare the effect of different tube lengths (for example 12mm vs 24mm) on the same lens?
Originally by Photography Stack Exchange contributor. Source · Licensed CC BY-SA 4.0
Photography Stack Exchange contributor
15y ago
2 Answers
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I do believe there are some formulas you can use. To Matt Grum's point, I have not tested these with zoom lenses, and to my current knowledge, they apply only to prime (fixed focal length) lenses. You did not specifically specify zoom lenses, so...
The simplest way to calculate the magnification of a lens is via the following formula, with magnification \$M\$, total extension \$E_\textrm{total}\$, and focal length \$f\$:
$$ M = \frac{E_\textrm{total}}{f} $$
To calculate the magnification with an extension tube, you need to know the total extension \$E_\textrm{total}\$... that is, the extension provided by the lens itself (\$E_\textrm{intrinsic}\$), as well as that provided by the extension tube, \$E_\textrm{tube}\$. Most lens statistics these days include the intrinsic magnification. If we take Canon's 50mm f/1.8 lens, the intrinsic magnification is 0.15×. We can solve for the lens's built-in extension like so:
$$ \begin{align} 0.15 &= \frac{E_\textrm{intrinsic}}{50} \\ E_\textrm{intrinsic} &= 50\times 0.15 \\ E_\textrm{intrinsic} &= 7.5\textrm{ mm} \end{align} $$
The magnification with additional extension can now be computed as follows:
$$ M = \frac{E_\textrm{intrinsic} + E_\textrm{tube}}{f} $$
If we assume 25 mm of additional extension via an extension tube:
$$ \begin{align} M &= \frac{7.5\textrm{ mm} + 25\textrm{ mm}}{50 \textrm{ mm}} \\ &= \frac{32.5\textrm{ mm}}{50\textrm{ mm}} \\ &= 0.65\,\times \end{align} $$
A fairly simple formula that allows us to calculate magnification fairly easily, assuming you know the intrinsic magnification of the lens (or its intrinsic extension.) If we assume the wonderful 50 mm lens is the lens you are extending, to create a 1:1 macro magnification, you would need 50 mm worth of extension. The problem here is that if you add too much extension, the plane of the world that is in focus (the virtual image) might just end up inside the lens itself. Additionally, this assumes a "simple" lens, one with very well-defined and well-known characteristics (i.e. a simple single-element lens.)
In a real-world scenario, having a clear understanding of any particular lenses characteristics is unlikely. With lenses that focus internally, or zoom lenses, the simple formula above is insufficient to allow you to calculate exactly what your minimum focusing distance and magnification can be for any given lens, focal length, and extension. There are too many variables, most of which are likely to be unknown, to calculate a meaningful value.
Here are some resources that I have found that provide some useful information that might help in your endeavor:
- Lens Tutorial
- Some great mathematics for lenses, including MFD and Mag
- Wikipedia: Magnification
- Forum Post about Extension, Magnification, MFD
- Limited applicability, assumes too much
- Forum post about Extension and MDF
- Limited applicability, assumes too much
Originally by user124. Source · Licensed CC BY-SA 4.0
user124
15y ago
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Generated from our catalog & community — verify before relying on it.
Yes—there are useful general rules, but they are more approximate than teleconverter math and depend on the lens design.
For a simple prime lens, added extension increases magnification roughly in proportion to tube length. A common approximation is:
magnification ≈ total extension / focal length
So, on the same lens, a 24mm tube gives about twice the added magnification of a 12mm tube. Shorter focal lengths are affected more strongly by a given tube length than longer focal lengths.
Extension tubes also reduce the minimum focusing distance, letting the lens focus closer. This follows the lens formula:
1 / subject distance + 1 / image distance = 1 / focal length
The tube increases image distance, so the subject distance must decrease.
Important caveat: real lenses are not all simple lenses. Internal focusing, floating elements, and zoom designs can change the result, and some lenses effectively change focal length as they focus. So exact magnification and closest-focus distance are lens-dependent, especially with zooms.
In short: yes, you can compare tube lengths on the same lens, and the effect is roughly proportional to extension, but exact numbers vary by lens.
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